I was looking at a mark scheme for a question I was stuck on, and I came across this. You are asked to work out the value of $\tan 75^\circ$ after you've worked out $\cos 15^\circ$ and $\sin 15^\ci
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Tan (90- Ө) = Cot Ө and Cot (90- Ө) = Tan Ө
Cot 90 - Cot 90 Degrees Value of Cot 90 Degrees
10.3: The Six Circular Functions and Fundamental Identities - Mathematics LibreTexts
10.3: The Six Circular Functions and Fundamental Identities
Find the ratios for tan 90°, cosec 90°, sec 90° and cot 90°.
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Cot 90 - Cot 90 Degrees Value of Cot 90 Degrees
Prove tanx=cot(90-x) - The Student Room
